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shepuryov [24]
3 years ago
6

A spinner is divided into 4 sections using the

Mathematics
2 answers:
cestrela7 [59]3 years ago
7 0

Answer:

The answer is 0.88 Hope this helps any T4L students!

andreev551 [17]3 years ago
6 0

Answer:

0.88

Step-by-step explanation:

Given:

A spinner is divided into 4 sections using the  colours: red, orange, yellow, and green. After  50 trials, the spinner landed on red 10 times,  on orange 16 times, on yellow 6 times, and  on green 18 times.

To find: probability of the spinner not landing  on yellow

Solution:

Probability is the chance of occurrence of some event.

Total number of outcomes = 50

Number of favourable outcomes = 50 - 6 = 44

Probability of the spinner not landing  on yellow = Number of favourable outcomes / Total number of outcomes = \frac{44}{50}=\frac{22}{25}=0.88

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a) In hypothesis testing the null hypothesis is never accepted. It is rejected or not rejected. In this case, couldn't be rejected, so it is possible that both machines produce the same fraction of defective parts. It is reasonable to conclude that both machines produce the same fraction of defective parts, although this test doesn't conclude this.

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c) -0.008\leq \pi_1-\pi_2\leq 0.054

Step-by-step explanation:

<em>In this problem we have to do a Test of Differences between Proportions</em>

<em />

The first step is to state the null and alternative hypothesis

H_0: \pi_1-\pi_2=0\\\\H_1:  \pi_1-\pi_2\neq 0

The null hypothesis represents the case where both machines are expected to produce the same amount of defective parts.

The second step is determine the significance level. In this case is α=0.05.

The third step is to calculate the difference in the proportions

p_1-p_2=(15/300)-(8/300)=0.050-0.027=0.023

The fourth step is to estimate the standard deviation of the difference between proportions.

s_{p_1-p_2}=\sqrt{\frac{p(1-p)}{n_1}  +\frac{p(1-p)}{n_2} }}

As n_1=n_2, we can calculate p as p=(p_1+p_2)/2=(0.050+0.027)/2=0.0385.

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s_{p_1-p_2}=\sqrt{\frac{p(1-p)}{n_1}  +\frac{p(1-p)}{n_2} }}\\\\s_{p_1-p_2}=\sqrt{\frac{2*0.0385(1-0.0385)}{300}}=0.0157

The fifth step is to compute p, the probability (or probability value).

z=(p_1-p_2)/s_{p_1-p_2}=0.023/0.0157= 1.465

A z table can be used to find that the two-tailed probability value for a z=1.465 is P(x>|z|)=0.143.

The probability value (P-value) is 0.143. As it is bigger than the significance level (0.05),  the effect is not significant. We can not reject the hypothesis.

To construct a 95% CI we can write:

(p_1-p_2)-z*s_{p_1-p_2}\leq \pi_1-\pi_2\leq (p_1-p_2)+z*s_{p_1-p_2}

For a 95% CI, z=1.96. The estimated standard deviation is the same calcaulated before. Now we can calculate:

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