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alexandr402 [8]
3 years ago
9

What is the inverse function of y=x^2-7

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0
With inverse functions you just swap 'x' and 'y' and solve for 'y'.

\sf y=x^2-7

Swap 'x' and 'y':

\sf x=y^2-7

Add 7 to both sides:

\sf x+7=y^2

Take the square root of both sides:

\sf y=\boxed{\sf\pm\sqrt{x+7}}
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steposvetlana [31]

Answer:

3rd, 4th, and 5th options.

Step-by-step explanation:

The way this was formatted was a little weird, but the 3rd, 4th, and 5th options are correct I think.

If there was 358.92 left, it has to be divided 3 ways (after subtracting 451.89 - 358.92). So that means that 3c or c+c+c could be correct, as well as using dis. property to switch around the last one I guess.

if this helped, brainliest is appreciated.

4 0
3 years ago
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What are the roots of the equation?<br><br> x^2+24=−11x<br><br> Enter your answers in the boxes.
docker41 [41]
<span>The <u>correct answers</u> are:

x=-3 and x=-8.

Explanation<span>:

We can first write this in standard form, ax</span></span>²<span><span>+bx+c=0. To do this, we will add 11x to both sides:
x</span></span>²<span><span>+24+11x=-11x+11x
x</span></span>²<span><span>+11x+24=0.

Now we can factor this. Look for factors of c, 24, that sum to b, 11. Factors of 24 are:
1 and 24 (sum 25)
2 and 12 (sum 14)
3 and 8 (sum 11)
4 and 6 (sum 10).

The factors we need are 3 and 8, since they sum to 11. This gives us factored form:
(x+3)(x+8)=0.

Using the zero product property, we know that in order to have a product of 0, one or both of the factors must be 0. This means we have:
x+3=0 or x+8=0.

Solving the first equation:
x+3-3=0-3
x=-3.

Solving the second equation:
x+8-8=0-8
x=-8.</span></span>
8 0
3 years ago
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Yuliya22 [10]
What is 563 times 38 ?

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The quotient of c and 6​
Anna007 [38]

Answer:

c/6 or c divided by 6

Step-by-step explanation:

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3 years ago
The sum of 2x+7 and −x+12 is equal to 14 what is x?
Alekssandra [29.7K]

Answer:-5


Step-by-step explanation:

2x+7-x+12=14

x+19=14

x=-5

                 


4 0
3 years ago
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