What is the inverse function of y=x^2-7

1 answer:

3 0

With inverse functions you just swap 'x' and 'y' and solve for 'y'.

$\sf y=x^2-7$

Swap 'x' and 'y':

$\sf x=y^2-7$

Add 7 to both sides:

$\sf x+7=y^2$

Take the square root of both sides:

$\sf y=\boxed{\sf\pm\sqrt{x+7}}$

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Let P(x) denote the statement "2x+5 > 10." Which of the following is true?

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Answer: P(3) is True

Step-by-step explanation:

The given statement is an inequality denoted as P(x). To find out which of the options is true you have to evaluate each given value of X in the inequality and perform the arithmetic operations, then you have to see if the expression makes sense.

For P(0): Replace X=0 in 2x+5>10

2(0)+5>10

0+5>10

5>10 is false because 5 is not greater than 10

For P(3): Replace X=3 in 2x+5>10

2(3)+5>10

6+5>10

11>10 is true because 11 is greater than 10

For P(2): Replace X=2 in 2x+5>10

2(2)+5>10

4+5>10

9>10 is false