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Alisiya [41]
3 years ago
6

No trick. Pure math. Gud luck Solve it You are standing in one big palace where a king and his 5 queens stay. Each queen has 5 r

ooms. In each room there are 5 big cats. Each big cat has 5 little cats. Each cat has 4 legs.How many legs are there in the palace? Take ur time... Soalan Yr9. Siapa terrer Math sini sila jwb
Mathematics
2 answers:
Radda [10]3 years ago
6 0
Myself = 2 legs King = 2 legs Queen 5 x 2 = 10 legs Total Big cats = 5 queens x 5 rooms x 5 big cats = 125 big cats x 4 legs = 500 legs Little cats 125 x 5 x 4 = 2500 legs 3014 legs
umka2103 [35]3 years ago
3 0
King = 2legs
Queen×5 = 10 legs
stated "you are standing" =myself, 2 legs.
ttl = 14 legs.

each queen has 5 rooms and each room has 5 big cats.
5×5 = 25 cats per queen.
25 cats × 5queens = 125 cats.

each big cat has 5 little cats, so
125 × 5 = 625 little cats.

ttl number of cats, 125 + 625 = 750

each cat has 4 legs. So,

750 × 4 = 3000

total number of legs in the palace...

3000+14 = 3014 legs.
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F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

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1. \mathrm{Subtract\:}f\left(x+2\right)\mathrm{\:from\:both\:sides}\\
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2. \mathrm{Simplify}\\
F\left(x+1\right)=-xf+f+2x\\


3. \mathrm{Divide\:both\:sides\:by\:}x+1;\quad \:x\ne \:-1\\
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4. \mathrm{Simplify}\\
F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

Final Answer: F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

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