3 is my guess, tricky question tough?
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Cube= 1/6
coin= 1/2
1/2*3= 3/6
3/6+1/6= 4/6
4/6= 2/3
The answer is 4/6 or 2/3
Answer:
-43
Step-by-step explanation:
(-7) - 6(6)= -43
I believe the answer would be 200 feet
