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d1i1m1o1n [39]
3 years ago
7

Which is the value of this expression when p=-2 and q=-1?

Mathematics
2 answers:
Semmy [17]3 years ago
8 0
The answer to your question is D.4
USPshnik [31]3 years ago
4 0

Answer:

The correct answer is D.4 DID THE TEST!

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Graph Data ALG 2 Please Help!
Sergio039 [100]

Answer:

1.  Figure 3

2. 2881.4 cm³

Step-by-step explanation:

The graph in figure 3 has a curve that fits the data best because it captures most of the points unlike the other two curves.

The curve in figure 3 has the equation;

y=-16.9x^2 +430x+523

2.

When using x=8, substitute the value of x in the equation with 8 to get

y = -16.9*64 + 430*8 + 523

y= 2881.4

= 2881.4 cm³

5 0
3 years ago
Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func
mote1985 [20]

Solution:

The given Polynomial is :

f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})

By Rational Root theorem the  of Zeroes of the Polynopmial are:

\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4

But , f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5}).

8 0
3 years ago
Read 2 more answers
Who won the Superbowl in 1996
Sophie [7]

The Dallas Cowboys.

7 0
3 years ago
Read 2 more answers
Solve the equation by completing the square. Round to the nearest hundredth if necessary. 3x^2 - 6x - 24 = 0
Fofino [41]

x= 4, -2 or 3(x-4)(x+2)

8 0
3 years ago
How does scale factor affect the change in area?​
MrRa [10]
<h3>Answer:</h3>

<u>It squares the amount you scaled it by.</u>

<h3>Step-by-step explanation:</h3>

For example, imagine that you had 2 by 2 square, and then you put it through a scale factor of 2.

Now each side length would be double of what it once was.

But when you multiply the new lengths together, the area would be of 4 times more.

(Original Equation)  2 * 2 = 4

(Scale Factor of 2)   4 * 4 = 16

So when the scale factor is made, the area would be squared to the multiple that you scaled it by.

<em>***A square root is a number times itself.</em>

<em>(eg): 3 * 3 = </em><em>9</em>

<em>        15 * 15 = </em><em>225</em>

<em>9 and 225 would be the square root in these problems.</em>

7 0
3 years ago
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