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Yuri [45]
3 years ago
5

Distribute 2 (9x^2 + 3).

Mathematics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

18x^2+6

Step-by-step explanation:

2(9x^2+3)

multiply each term in parentheses by 2

2 x 9x^2+2 x 3

calculate product

18x^2+2 x 3

multiply numbers

18x^2+6

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State domain of -5 0 , -4 2, 0 10 , 3 16
balandron [24]
The domain is another name for the values of x

In the points ( -5 , 0) , ( -4 , 2) , (0 , 10) , and (3 , 16)

-5, -4, 0, and 3 are the domains
7 0
3 years ago
Jonathan increased his rate of walking by 25% at halfway to his destination and therefore arrived half an hour earlier than was
Flura [38]

Answer:

1.67 hours

Step-by-step explanation:

Let the original speed of Jonathan = x units/hr

Let the original time taken by Jonathan = y hours

Let the distance = D units

Formula for distance is given as:

Distance = Speed \times Time

Given that half the distance is covered by original speed.

\Rightarrow \dfrac{D}{2} = \dfrac{x}{2}\times \dfrac{y}{2}\\\Rightarrow D = \dfrac{xy}{2} ..... (1)

Half the distance is covered by increasing the rate by 25%.

i.e. increased speed:

\dfrac{5}{4}x\ units/hr

Hence, Time taken:

\dfrac{y}{2}-\dfrac{1}{2}

Distance traveled is half of the total distance:

\Rightarrow \dfrac{D}{2} = \dfrac{5x}{4}\times (\dfrac{y}{2}-\dfrac{1}{2})\\\Rightarrow D = \dfrac{5x}{2}\times (\dfrac{y}{2}-\dfrac{1}{2}) .... (2)

Dividing (1) by (2):

\dfrac{xy\times 4}{2\times 5x(y-1)} = 1\\\Rightarrow 2y=5y-5\\\Rightarrow 3y=5\\\Rightarrow y =1.67\ hours

5 0
3 years ago
PLEASE HELP question is in the picture
Ivanshal [37]

Hope this helps and please give brainlist

3 0
3 years ago
You want to compute a 90% confidence interval
Vesnalui [34]

Answer:

you do it your self just saying you good at it believe in yourself

7 0
3 years ago
I need help with this one math question please!
den301095 [7]

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

\frac{x-5}{(x-5)(x+2)} × \frac{x+2}{(x+4)(x-3)}

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

\frac{1}{(x+4)(x-3)} = \frac{1}{x^2+x-12}

3 0
3 years ago
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