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3 years ago

Distribute 2 (9x^2 + 3).

Mathematics

1 answer:

beks73 [17]3 years ago

5 0

Answer:

18x^2+6

Step-by-step explanation:

2(9x^2+3)

multiply each term in parentheses by 2

2 x 9x^2+2 x 3

calculate product

18x^2+2 x 3

multiply numbers

18x^2+6

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State domain of -5 0 , -4 2, 0 10 , 3 16

balandron [24]

The domain is another name for the values of x

In the points ( -5 , 0) , ( -4 , 2) , (0 , 10) , and (3 , 16)

-5, -4, 0, and 3 are the domains

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3 years ago

Jonathan increased his rate of walking by 25% at halfway to his destination and therefore arrived half an hour earlier than was

Flura [38]

Answer:

1.67 hours

Step-by-step explanation:

Let the original speed of Jonathan = $x$ units/hr

Let the original time taken by Jonathan = $y$ hours

Let the distance = $D$ units

Formula for distance is given as:

$Distance = Speed \times Time$

Given that half the distance is covered by original speed.

$\Rightarrow \dfrac{D}{2} = \dfrac{x}{2}\times \dfrac{y}{2}\\\Rightarrow D = \dfrac{xy}{2} ..... (1)$

Half the distance is covered by increasing the rate by 25%.

i.e. increased speed:

$\dfrac{5}{4}x\ units/hr$

Hence, Time taken:

$\dfrac{y}{2}-\dfrac{1}{2}$

Distance traveled is half of the total distance:

$\Rightarrow \dfrac{D}{2} = \dfrac{5x}{4}\times (\dfrac{y}{2}-\dfrac{1}{2})\\\Rightarrow D = \dfrac{5x}{2}\times (\dfrac{y}{2}-\dfrac{1}{2}) .... (2)$

Dividing (1) by (2):

$\dfrac{xy\times 4}{2\times 5x(y-1)} = 1\\\Rightarrow 2y=5y-5\\\Rightarrow 3y=5\\\Rightarrow y =1.67\ hours$

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3 years ago

PLEASE HELP question is in the picture

Ivanshal [37]

Hope this helps and please give brainlist

3 0

3 years ago

You want to compute a 90% confidence interval

Vesnalui [34]

Answer:

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3 years ago

I need help with this one math question please!

den301095 [7]

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

$\frac{x-5}{(x-5)(x+2)}$ × $\frac{x+2}{(x+4)(x-3)}$

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

$\frac{1}{(x+4)(x-3)}$ = $\frac{1}{x^2+x-12}$

3 0

3 years ago