Question

PLEASE HELP!! SO IMPORTANT! The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70cm^3 of water. Find the percent of the cup that is filled with water after 3 seconds. Use 3.14 for pi and round your final answer to the nearest percent.

Answer 1

Note : The dimensions of the cup are not given.

Now we have been given that, after 2 seconds, the cup has a volume of 70 cubic cm.

As the cup is filled at a constant rate, in 1 second, it fills

$\frac{70}{2}=35$ = 35 cubic cm.

Hence, in 3 seconds, it fills $35\times3=105$ cubic cm.

To find the percent we need the dimensions of the cup.

Answer 2

Answer:

Now we have been given that, after 2 seconds, the cup has a volume of 70 cubic cm.

As the cup is filled at a constant rate, in 1 second, it fills

= 35 cubic cm.

Hence, in 3 seconds, it fills  cubic cm.

To find the percent we need the dimensions of the cup.