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3 years ago

Explain me how to used a graph on the function f(x) to find f(3)?

Mathematics

2 answers:

Zanzabum3 years ago

3 0

Just plug in 3 into the formula that you have been given and solve the equation.

Vikentia [17]3 years ago

3 0

Answer:

Sample Response: For f(3), the input is 3 and you are looking for the output. To determine the function's value when x = 3, go to the value of 3 on the x-axis and then locate the graph for that value of x. Determine the value of y from the y-axis at that location on the graph.

- credit to Edge-nuity (is that how you spell it?)

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Consider the line y=-4/7x+4.

Wittaler [7]

Answer:

1). y = -4/7x 2). y = 7/4x - 65/4

Step-by-step explanation:

1). When a line is parallel, the slope remains the same.

y = -4/7x + b

-4 = -4/7(7) + b

-4 = -4 + b

0 = b

The equation is simply y = -4/7x.

2). When a line is perpendicular, the slope becomes the exact opposite.

y = 7/4x + b

-4 = 7/4(7) + b

-4 = 49/4 + b

-65/4 = b

The equation is y = 7/4x - 65/4.

7 0

2 years ago

I’m confused on this one

erastovalidia [21]

In the chart of the triangle it shows that the variable b is the base. It also give us the equation for area 1/2bh (half of base * height)

Now we just plug in the values we are given

1/2bh

1/2(10*13)

1/2(130)

The area of the triangle is 65 ft

4 0

2 years ago

Read 2 more answers

Which is equivalent to 8.03 x 10-8?

Veronika [31]

Answer:

16.06

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5 0

3 years ago

A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.

zzz [600]

Answer:

$CI=(66.54,78.46)$

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , $\bar{X}=72.5\%$ , s=5.8%