It takes 4.3 seconds for the rocket to return to earth.
The equation is:
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:
We will use the quadratic formula to solve this. The quadratic formula is:
Plugging in our information we have:
x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
n=9 would be your answer. Hope I helped
The value of x is 0.65
<u>Step-by-step explanation:</u>
This solution is given by solving the given problem using BODMAS rule.
This means that the steps to be followed to find the solution should be in the order of BODMAS rule.
B- Bracket, O- of, D- Division, M- Multiplication, A- Addition, S- Subtraction.
This rule states that the 1st operation must be done for Brackets.
⇒ -3.75+2(-4x+6.1)-3.25 = 0
⇒ -3.75 -8x + 12.2 -3.25 = 0
The addition operation should be performed next and then followed by subtraction.
⇒ -8x -7+ 12.2 = 0
<u>To find the value of x :</u>
Keeping the x term alone on one side and moving the constants on other side,
⇒ -8x = -12.2 + 7
⇒ -8x = -5.2
⇒ x = 5.2/8
⇒ x = 0.65
Well the opposite of a square is a square root so it would be s=[square root of]60