4 years ago

If two parents are homozygous dominant for a recessive trait , what is the probability they child does not have this trait ?

1 answer:

6 0

If you set up a punnett square, the results from a cross between these parents AA x AA (homozygous dominant) would be something like (AA, AA, AA, AA)

From the results, we can see there is a 100% chance the child would have the trait.

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