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ale4655 [162]
3 years ago
7

Find the output values of the exponential function g(x) = 4,096x for x = 0, 0.25, 0.50, 0.75, and 1.

Mathematics
2 answers:
Alex Ar [27]3 years ago
4 0

Hello,g(x)=4096^xg(0)=1g(0.25)=(2^12)^1/4=2^(12/4)=2^3=8g(0.50)=(2^12)^(1/2)=2^6=64g(0.75)=(2^12)^(3/4)=2^9=512g(1)=4096^1=4096.

Ratling [72]3 years ago
4 0

Answer:

Output values for g(x) = 4096^x

Step-by-step explanation:

We are given the following information in the question:

We have to evaluate the given exponential function.

g(x) = 4096^x

g(0) = 4096^0 = 1\\\\g(0.25) = 4096^{0.25} = 8\\\\g(0.50) = 4096^{0.50} = 64\\\\g(0.75) = 4096^{0.75} = 512\\\\g(1) = 4096^1 = 4096

These are the required output values.

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