All categories

4 years ago

* this is pretty difficult for me , provide details if necessary * // ANSWER ASAP //

Mathematics

1 answer:

fredd [130]4 years ago

5 0

Answer:

Step-by-step explanation:

1 radian = 180/π

Multiplying both sides by 25π/18

We'll get,

25π/18 (r) = (180/π)×(25π/18)

= (180×25)/18

= 10×25

= 250 degrees

You might be interested in

PLEASE HELP the answer is not 1/4^-2

hram777 [196]

Answer:

4^3÷4^5

4^(3-5)

4^-2

1/4^2

6 0

3 years ago

Read 2 more answers

Write the expression as the sine, cosine, or tangent of an angle.

Naily [24]

Step-by-step explanation:

the formula is :

tan (a+b) =

(tan (a) + tan (b)) / ( 1 - tan (a) . tan (b))

therefore

tan (π/5) + tan (π/2)) / (1-tan (π/5) tan (π/2))

= tan (π/5 + π/2)

4 0

3 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

3 years ago

Which of the following is a rational number?

olga nikolaevna [1]

Answer:

Step-by-step explanation:

when you solve B you get 15 and for all the other ones you get a non-terminating decimal

8 0

3 years ago

Expand the following: 3(16x-24)

Fynjy0 [20]

Answer:

48x-72

Step-by-step explanation:

u multiply 3 by 16x then multiply 3 by 24 and bring down your minus sign

6 0

3 years ago