Find the least common multiples of 4, 10, 12, 15
multiples of 4:
4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80
multiples of 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120
multiples of 12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120
multiples of 15: 15, 30, 45, 60, 75, 90, 105, 120, 135, 150
The least common multiple of 4, 10, 12, and 15 is 60.
4 x 15 = 60
10 x 6 = 60
12 x 5 = 60
15 x 4 = 60
Answer= 12
111-15= 96
96: 8= 12
so each book cost $12
Answer:
1/1+1/1+1/1+1/1
Step-by-step explanation:
Answer:
<u>maximum of 2 bicycle</u>
Step-by-step explanation:
Given the average cost per bicycle modeled by the equation
C(x) = 0.5x^2-1.5x+4.83
C(x) is in hundreds of dollars
x is number of bicycle
The number of bicycle that will minimize the cost occurs when dC/dx = 0
dC/dx = 2(0.5)x - 1.5
dC/dx = x - 1.5
Since dC/dx = 0
0 = x - 1.5
x = 0+1.5x = 1.5
Hence the shop should buy <u>maximum of 2 bicycle</u> to minimize the cost
Answer:
C
Step-by-step explanation:
