9514 1404 393
Answer:
Step-by-step explanation:
You have to realize that the absolute value function will change the sign of its argument only if that argument is negative.
108. |x -7| = x -7 . . . . . true for x-7≥0
x ≥ 7 . . . . makes the statement true
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1a. When m < 9, the value 6m is less than 54, so 6m-54 < 0. That means the absolute value function changes the sign of its argument:
54 -6m . . . . . simplified form for m < 9
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1b. |y -x| = y -x . . . when y > x, the argument of the absolute value is positive
Answer:
1 7/15
Step-by-step explanation:
2-1=1
then you make 2/3 and 1/5 have the same denominator -
5*3=15
?/15 ?/15
multiply 2 by 5 which is 10, so 10/15
then multiply 1 by 3 which is 3/15
subtract 3/15 from 10/15 which is 7/15
Answer:
0.41
Step-by-step explanation:
0.82 = 0.2 x 0.41
0.82 / 0.2
= ( 0.2 x 0.41 ) / 0.2
= 0.41
Replace each of the x values given to see if they give 0.
0=(2/3)³+(2/3)²-1
0=(8/27)+(4/9)-1
0≠-0.259
0=(1)³+(1)²-1
0≠1
Therefore, you can see that the solution would have to be between 2/3 and 1.
Hope I helped :)
