Answer:
- f[1] = 3
- f[n] = 2·f[n-1] +4
- 108
Step-by-step explanation:
We observe that first differences of the given numbers are ...
10 -3 = 7
24 -10 = 14
52 -24 = 28
That is, each difference is 2× the previous one. This suggests an exponential relation that has a base of 2.
We notice that doubling a term doesn't give the next term, but gives a value that is 4 less than the next term. So, we can get the next term by doubling the previous one and adding 4.
Then our recursive relation is ...
f[1] = 3 . . . . the first term
f[n] = 2×f[n-1] +4 . . . . double the previous term and add 4
The next term is 2·52 +4 = 108.
Equations with a number in brackets that is less then one is a decaying function.
Y=200(0.5)2t Decay
Y=12(2.5)t6 Growth
Y=(0.65)t4 decay
Hope this helps!
{ x + y = 5 * ( -3 )
3x + 2y = 10
- 3 x - 3 y = - 15
3 x + 2y = 10
_______________
- y = - 5 * ( -1 )
y = 5
For x :
3 x + 2 y = 10
3 x + 2 * ( 5 ) = 10
3 x + 10 = 10
3 x = 10 - 10
3 x = 0
x = 0 / 3
x = 0
X = 0 and y = 5
hope this helps!
Answer:
she will insert 6 dollars into the machine
Step-by-step explanation:
819 is the answer because thats how many visitors he got
