Estimate 85,120 divided by 76

Barb is making a bead necklace. She strings 1 white bead,then 3 blue beads,then 1 white bead,and so on. Write the numbers for th

nataly862011 [7]

The numbers for the first eight beads that are white are; 1, 5, 9, 13, 17, 21, 25, 29

<h3>Arithmetic Sequence</h3>

We are told that she strings in this order;

1 white
3 blue
1 white bead

Now, after the first white bead, the next white bead is the 5th bead in total.

This means the difference in interval between white beads is; 5 - 1 = 4 beads

Thus, the numbers for the first eight beads that are white are;

1, (1 + 4), (1 + 4 + 4), (1 + 4 + 4 + 4).....

Thus, we have;

1, 5, 9, 13, 17, 21, 25, 29

Read more on arithmetic sequence at; brainly.com/question/7849474

8 0

2 years ago

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There are two approaches to solving the equation -3x + 10 = 4x - 20

rosijanka [135]

Answer:

You can take this equation into two approaches.

#1 subtracting 4x from both sides:

-3x+10=4x-20 (subtract 4x from each side)

-7x+10=-20 (then subtract 10 from each side)

-7x=-30 (then divide by -7 to get x by itself)

x=30/7

#2 Add 3x to both sides:

-3x+10=4x-20 (Add 3x to both sides)

10=7x-20 (then add 20 to each side)

30=7x (divide both sides by 7)

30/7=x

Either way you do it you will get x=30/7 as your answer.

Hope this helps ;)

7 0

3 years ago

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Priya is buying raisins and almonds to make trail mix. Almonds cost $5.20 per pound and raisins cost $2.75 per pound. Priya spen

Tanzania [10]

Answer:

3.48pounds

Step-by-step explanation:

given data

cost of Almonds= $5.2

cost of raisins= $2.75

total cost = $11.7

given that the relationship that represents the cost for the two quantities is

5.20a + 2.75r = 11.70

where a= almond

r= raisin

we are going to substitute a=0.41 in the expression to solve for r

5.20(0.41) + 2.75r = 11.70

2.132+2.75r=11.7

collect like terms

2.75r=11.7-2.132

2.75r=9.568

r=9.568/2.75

r=3.48

7 0

3 years ago

Solve x + 5x + 6 = 0

Dominik [7]

X+5x+6=0
x+5x=6x
6x+6=0
-6 -6
6x=-6
\6. /6
x= -1
so the answer would be -1

7 0

3 years ago

Below is the graph of f(x)=2In(x). how would you describe the graph of g(x)=4In(x)

Andreyy89

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... with that template in mind, let's see yours

$\bf \begin{array}{llll}
g(x)=&4ln(x)\implies &2(2)ln(x)\\
&\uparrow &\uparrow \\
&A&A
\end{array}$

A is twice as large as in f(x), thus the graph shrinks twice as much in g(x)

7 0

4 years ago

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