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Alekssandra [29.7K]

2 years ago

15

David leaves reading at 11 45am. he arrives at cardiff at 1 45pm. david drives at an average speed of 56 miles per hour. work ou

t the distance between bristol and cardiff

1 answer:

yan [13]2 years ago

3 0

Step-by-step explanation:

speed = distance/time

we know the speed and the time (11:45am to 1:45pm = 2 hours).

distance = speed × time = 56 m/h × 2 h = 112 miles

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What is the product of 5.86 × 10–7 and 3.1 × 104 1. Write the expression: (5.86 × 10–7)(3.1 × 104) 2. Rearrange the expression:

Reil [10]

Answer:

The value of the exponent of the base 10 for this product is -2.

Step-by-step explanation:

$5.86\,\,10^{-7}\,\,*\,\,3.1\,\,10^4=18.166\,\,10^{-7+4}=18.166\,\,10^{-3}$

Now, in order to represent this number in scientific notation, we need to reduce the coefficient 18.166 to a coefficient larger or equal to 1 and smaller strictly than 10, by using division or multiplications by powers of 10. In order to reduce it to 1.8166, we need to divide the original 18.166 by ten so we do the following in order not to change the given number (multiply and divide by ten at the same time):

$\frac{18.166\,\,10}{10} \,10^{-3}=1.8166\,*\,10\,*\,10^{-3}=1.8166\,\,10^{-2}$

3 0

3 years ago

Read 2 more answers

Help. Please. Thanks.

Musya8 [376]

950 * .05 = $47.5
550 * .04 = $22

$47.5 + $22 = $69.50 interest earned

answer: amount in 4% account = $550

6 0

3 years ago

5) Two machines M1, M2 are used to manufacture resistors with a design

Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that $\mu = 1050, \sigma = 100$

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1050}{100}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1050}{100}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that $\mu = 1000, \sigma = 120$

X = 1100

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1100 - 1000}{120}$

$Z = 0.83$

$Z = 0.83$ has a pvalue of 0.7967.

X = 900

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{900 - 1000}{120}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0

3 years ago

Suppose three marksmen shoot at a target. The ith marksman fires ni times, hitting the target each time with probability Pi, ind

astraxan [27]

Answer:

Distribution is NOT binomial.

Step-by-step explanation:

In order to be a binomial distribution, the probability of success for each individual trial must be the same. Since each marksman hits the target with probability Pi, the probability of success (hitting the target) is not necessarily equal for all trials. Therefore, the distribution is not binomial.

In this case, the distribution would only be binomial if Pi was the same for every "ith" marksman.

6 0

3 years ago

adoni [48]

Answer:

the correct answer would be 5 months

Hope this helps (:

4 0

3 years ago

Read 2 more answers