Graph the inequalitly y> 2/3x -1

What is the zero of the linear function?

zavuch27 [327]

Answer:

0 of the linear function is the start of the line your answer would be the end of the line

6 0

3 years ago

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Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!

7 0

3 years ago

Which expression is a difference of squares with a factor of 2x5?

Sedbober [7]

Answer:

${( \sqrt{3.5} })^{2} - {( \sqrt{1.5} )}^{2}$

Step-by-step explanation:

The difference of two squares identity is

${x}^{2} - {y}^{2} = (x - y)(x + y)$

When we let

$\sqrt{3.5}$

and

$\sqrt{1.5}$

, we get:

${( \sqrt{3.5} )}^{2} - {( \sqrt{1.5}) }^{2} = (3.5 - 1.5)(3.5 + 1.5)$

This will simplify to give us the required factors

${( \sqrt{3.5} )}^{2} - {( \sqrt{1.5}) }^{2} =2 \times 5$

7 0

3 years ago

A fraction is shown 5/9 which number equivalent to the fraction

Alexandra [31]

Answer:

10/18 or 25/45

Step-by-step explanation

5 0

2 years ago

What is the slope of the line that contains the points (1,-1) and (-2,8)? (Also can you show me how you got it please?)

ArbitrLikvidat [17]

The answer is -3

You use the formula y1-y2
———
x1-x2
-1 and 8 are your y’s
1 and -2 are your x’s

Your equation should look like this
-1-8 -9
—— = —— = -3
1-(-2) 3

I plugged the y’s and x’s into the formula.
I hope this helps!!

3 0

3 years ago