3276800/8 = 409600 (how many bacteria in an hour)
Then just multiply that number by the amount of hours you want to solve for
9 hours = 3686400
10 Hours = 4096000
f(0) = 2(3)(0) = 0 ⇒ (0, 0)
f(1) = 2(3)(1) = 6 ⇒ (1, 6)
<u>rate of change from x = 0 to x = 1</u>
=
=
= 6
******************************************
f(2) = 2(3)(2) = 12 ⇒ (2, 12)
f(3) = 2(3)(3) = 18 ⇒ (3, 18)
<u>rate of change from x = 2 to x = 3</u>
=
=
= 6
*****************************************
Since it is the same line, they will have the same slope (aka rate of change).
Sq32/8 = sq4
It would be c. 2
Answer:
Dan is correct
Step-by-step explanation:
From the question, we have:
![Hours:1\ 2\ 3\ 4\ 5](https://tex.z-dn.net/?f=Hours%3A1%5C%202%5C%203%5C%204%5C%205)
Required
The average
The average hour is calculated using:
![\bar x = \frac{\sum x}{n}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B%5Csum%20x%7D%7Bn%7D)
So, we have:
![\bar x = \frac{1+2+3+4+5}{5}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B1%2B2%2B3%2B4%2B5%7D%7B5%7D)
![\bar x = \frac{15}{5}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B15%7D%7B5%7D)
![\bar x = 3](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%203)
<em>Dan calculated the mean as 3; while Bret calculated the mean as 4.</em>
<em>Hence, we can conclude that Dan s correct</em>
Answer:
73.25
Step-by-step explanation:
Add all numbers and divide by 4 to get the average grade.