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pishuonlain [190]
3 years ago
13

What is the answer to 5c-25=2c+6

Mathematics
1 answer:
Masja [62]3 years ago
4 0
Subtract 2c from both sides
5c-25-2c=2c+6-2c
3c-25=6
add 25 to both sides
3c-25+25=6+25
3c=31
Divide both sides by 3
3c/3=31/3
c=31/3
hope this helps!
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\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6}  }}  \huge{) } \small{{}^{  {}^{ {}^{ {}^{ - 2} } } } }\\  \\  \\ \huge{(} \small{   \frac{4 \times m {}^{1}  \times n {}^{1} }{ {m}^{ - 2} \times  {n}^{6}  }}  \huge{)} \small{^{  {}^{ {}^{ {}^{ - 2} } } }} \\  \\  \\  \huge{(} \small{4 \times  {m}^{1 - ( - 2)}  \times  {n}^{1 - 6}} \huge{)} \small{ {}^{  {}^{ {}^{ {}^{ - 2} } } } } \\  \\  \\   \huge{(} \small{ 4 \times  {m}^{1 + 2}  \times  {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{  {}^{  {}^{ - 2} } }  } } \\  \\  \\ \small{  {(4)}^{ - 2} \times  ({m}^{3} ) ^{ - 2} \times  {(n{}^{ - 5} )}^{ - 2}    } \\  \\  \\  \frac{1}{ {4}^{2} }  \times  {m}^{ - 6}  \times  {n}^{ 10}  \\  \\  \\  \frac{1}{16}  \times  \frac{1}{ {m}^{6} }  \times  {n}^{10}  \\  \\  \\  \frac{ {n}^{10} }{16{m}^{6} }







\text{ Hence, option B is correct }
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