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3 years ago

The budgeted unit sales of Weller Company for the upcoming fiscal year are provided below:

Business

1 answer:

Sati [7]3 years ago

7 0

Answer:

Weller Company

Selling and Administrative Expense Budget for the upcoming year:

First Quarter

Variable = $302,400 (($2.80 x (29,000 + 30,000 +22,000 + 27,000))

Fixed:

Advertising = $56,000 ($14,000 x 4)

Executive Salaries = $188,000 ($47,000 x 4)

Depreciation = $112,000 ($28,000 x 4)

Insurance = $10,000 ($5,000 x 2)

Property Taxes = $7,800

Total = $672,200

Explanation:

A budget is a projection into the future about the activities of an entity. It is used for planning and decision making, especially when the budget is compared with the actual performances to obtain variances.

The total variable for the year is obtained by adding up the budgeted unit sales for the quarters and multiplying by the variable expense per unit.

The fixed costs total $373,800. The Advertising, Executive Salaries, and Depreciation costs would be incurred each quarter. So their sums were obtained by multiplying a quarter's total cost by 4.

Insurance cost would be incurred only in two quarters and Property Taxes in one quarter only.

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1 year ago

A car dealer who sells only late-model luxury cars recently hired a new salesman and believes that this salesman is selling at l

Natasha2012 [34]

Answer:

$t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3$

Explanation:

Data given and notation

$\bar X=5000$ represent the sample mean

$s=800$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =5600$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:

Null hypothesis: $\mu \geq 5600$

Alternative hypothesis: $\mu < 5600$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3$

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Margaret [11]

Answer:

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