Match each point with one of the following fractions: 5/6, 7/12, 1/8, 5/16

Mathematics

2 answers:

Anton [14]3 years ago

6 0

Answer is B. second one

A = 1/8, B = 5/16, C = 7/12, D = 5/6
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liubo4ka [24]3 years ago

6 0

A for #1
and B for #2
hope it helped!

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I need help please :/

OleMash [197]

Part (a)

Plug in y = 0 and solve for x. Use the zero product property

y = x(x+3)(x-2)

0 = x(x+3)(x-2)

x(x+3)(x-2) = 0

x = 0 or x+3 = 0 or x-2 = 0 .... zero product property

x = 0 or x = -3 or x = 2

The three roots or zeros are x = 0 or x = -3 or x = 2

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Part (b)

The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.

Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.

So that's why the graph does <u>not</u> match with the function in part (a)

7 0

3 years ago

I need help with number 5, and 6. <br><br> Please and thank you.

erastovalidia [21]

Answer:

5 - 1 year

6 - 738.92

Step-by-step explanation:

5: 260 = 250(1.04)^t

Divide both sides by 250, and we get 1.04. So t must be 1.

6: x + 45 = x(1.03)²

Solve to find x

6 0

2 years ago

Hey can you please help me posted picture of question

Dmitry_Shevchenko [17]

Answer:
The solutions are:
$\frac{3 + i}{2}$ and $\frac{3 - i}{2}$

Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
2x² - 6x + 5 = 0

By comparison:
a = 2
b = -6
c = 5

Now, to get the solutions of the equation, we will have to use the quadratic formula shown in the attached image.

By substituting in the formula, we would find that:
either x = $\frac{6 + \sqrt{(-6)^2 - 4(2)(5)} }{2(2)} = \frac{3 + i}{2}$

or x = $\frac{6 - \sqrt{(-6)^2 - 4(2)(5)} }{2(2)} = \frac{3 - i}{2}$

Hope this helps :)