Answer:
Sum of 100 terms of the sequence = 15050
Step-by-step explanation:
Given expression which represents a sequence is,

So the sequence will be,
2, 5, 8, 11, 14..........
So, the given sequence is an arithmetic sequence with,
First term of the sequence 'a' = 2
Common difference 'd' = 5 - 2 = 3
Sum of 'n' terms of an arithmetic sequence is given by,
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Here, n = number of terms
a = first term
d = common difference
= ![\frac{100}{2}[2(2)+(100-1)(3)]](https://tex.z-dn.net/?f=%5Cfrac%7B100%7D%7B2%7D%5B2%282%29%2B%28100-1%29%283%29%5D)
= 50[4 + 297]
= 15050
Therefore, sum of 100 terms of the sequence = 15050
Answer:
Step-by-step explanation:
It might be B
<h3>If this helped, PLEASE make this the BRAINLIEST answer!</h3>
0.4641. would be your answer
Adding up there are 41769 five digit numbers with atleast one zero in it. Therefore the probability that a five-digit number has at least one zero in it is 0.4641.
This is an arithmetic the common difference is 11.
so 19-11 is 8
8-11 is 3 etc...
1. change the fractions into decimals- 3/4=0.75 1/4=0.25
2. 2 x 0.75= 1.50
3. 1.50-0.25=1.25
answer- 1.25