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Sholpan [36]
3 years ago
10

2. Tonya runs 8 kilometers in 60 minutes. At this rate, how long would it take her to run 2 kilometers?​

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

15 minutes

Step-by-step explanation:

60/4=15 8/4=2

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A recipe for sugar requires 2 cups of flour forever 2/3 cups of sugar at this rate how many cups of sugar should be used to 5 cu
Marta_Voda [28]

Answer:

10/6 cups of sugar is the answer to this equation being the correct answer.

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5 0
3 years ago
Find f(12) = 3/4 x + 2
AlekseyPX

Answer:

f(12) = 11

Step-by-step explanation:

To solve this question:

  1. Substitute x = 12 into the equation: f(12) = 3/4 (12) + 2
  2. Simplify: 3/4 × 12 = 36/4 which is 9 → f(12) = 9 + 2
  • f(12) = 11

Hope this helps!

5 0
3 years ago
Read 2 more answers
In the Chang’s family budget, 0.6% of the expenses are for internet service. What fraction of the family’s expenses is for inter
Hitman42 [59]
The answer would be 60/100.
8 0
3 years ago
Read 2 more answers
a jug holds 4 quarts How many liters of milk dose the jug hold ? round your answer to the nearest hundredth of a liter 1 L=1.06
svetoff [14.1K]

Answer:

Please read the explanation to clarify.

Step-by-step explanation:

What you would have to do is multiply 1.06 by 4 to get 4.24. However, if you search up the exact conversion on g00gle, "how many liters are in 4 quarts?", you get the exact number of 3.78541, which can be rounded to 3.78. I believe if this is more of an exam thing, you should go with the first answer I gave, 4.24, and show how you multiplied to show your work. However, if you would like to use the second answer, it is completely up to you. Either way,  I hope this helped, and if you have any further questions please don't hesitate to let me know. :)

7 0
3 years ago
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Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 50.7 d
Svet_ta [14]

Answer: The mean of the frequency distribution is 51.7°.

The computed mean 51.7° is greater than the actual mean 50.7° .

Step-by-step explanation:

The given table :

  Low Temperature ​(°​F)      Frequency     Mid -value  

      Class interval                  f                        x                  fx

          40-44                           2                     42.5               85

          45-49                           7                     47.5               95                      

          50-54                          9                     52.5               105

           55-59                         5                     57.5                115

           60-64                          1                      62.5               25

\text{Now, Mean}=\dfrac{\sum fx}{\sum f}\\\\=\dfrac{85+332.5+472.5+287.5+62.5}{24}\\\\=\dfrac{1240}{24}=51.6666666667\approx51.7

The computed mean 51.7° is greater than the actual mean 50.7° .

5 0
3 years ago
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