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Novay_Z [31]
4 years ago
12

A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the ba

rbell. The chain has a total weight of 500 N. How much work (in J) is required to lift the barbell to a height of 2 m
Mathematics
1 answer:
stiv31 [10]4 years ago
4 0
In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.

W = Fd

The total force is 
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be

W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J

If the question is the additional work to reach 2 m from the initial 1 m, that would be

W = (2,220 N)(2 - 1 m) = 2,200 J
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Step-by-step explanation:

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ella [17]

ANSWER:

104

STEP-BY-STEP EXPLANATION:

Given:

Standard deviation (σ) = 700

Confidence level = 95%

Mean error (Eμ) = 135

We have for a confidence level of 95%:

\begin{gathered} \alpha=100\%-95\%=5\%=0.05 \\  \\ \alpha\text{/2}=\frac{0.05}{2}=0.025 \\  \\ \text{ The corresponding Z value for \alpha/2 = 0.025 is as follows:} \\  \\ Z_{\alpha\text{/2}}=1.96 \end{gathered}

Now, we calculate the minimum value of the sample size as follows:

\begin{gathered} n=\left(\frac{Z_{\alpha\text{/2}}\cdot\sigma}{E}\right)^2 \\  \\ \text{ We replacing:} \\  \\ \:n=\left(\frac{1.96\cdot 700}{135}\right)^2 \\  \\ \:n=103.2858\cong104 \end{gathered}

The minimum sample size needed is 104

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Step-by-step explanation:

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