Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
I believe it's D <span>.DNA repair enzymes often repair errors.
</span>I believe this because enzymes<span> remove incorrect bases with a few surrounding bases, which </span>are<span> replaced with the </span>correct<span> bases with the help of a DNA polymerase and the template DNA. When replication mistakes </span>are<span> not corrected, then it may result in </span>mutations<span>, which sometimes </span>can<span> have serious consequences.</span>
<span>First Generation OD (organizational development) focused on the individual organizational member's behavior and interpersonal relationships as it relates to productivity and efficiency. Second Generation OD focuses on the future of the organization and requires that the leader do a lot of planning and coordinating to lead the organization in the best possible direction.</span>
<span>The graph portrays
predation. The relationship shows that an
increase in the population of zebra
results in a subsequent increase in the lion population, and vice versa. This,
therefore, means that the lion population
is dependent on the zebra population due to an interaction (predation). The lion population
will always be lower than that of the zebra because of the inefficiencies of energy transfer up the trophic levels (exhibited by a
typical energy pyramid). </span>
The evolution of apes to man
