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SSSSS [86.1K]
3 years ago
13

Which of the following is equivalent to 6x 2 + x - 12 ?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0
6x^2+x-12=6x^2-9x+8x-12=3x(2x-3)+4(2x-3)\\\\=(2x-3)(3x+4)\\\\other\ method:\\\\6x^2+x-12\\a=6;\ b=1;\ c=-12\\\Delta=b^2-4ac\to\Delta=1^2-4\cdot6\cdot(-12)=1+288=289\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{289}=17

x_1=\frac{-1-17}{2\cdot6}=\frac{-18}{12}=-\frac{3}{2};\ x_2=\frac{-1+17}{2\cdot6}=\frac{16}{12}=\frac{4}{3}\\\\6x^2+x-12=6(x+\frac{3}{2})(x-\frac{4}{3})=2\cdot3(x+\frac{3}{2})(x-\frac{4}{3})\\\\=2(x+\frac{3}{2})\cdot3(x-\frac{4}{3})=(2x+3)(3x-4)
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Answer:

990

Step-by-step explanation:

M/J = 2/7

J = 3/4 L

L = M + 396

7M = 2J

J = 3.5M

3.5M = 3/4 L

L = 4/3(3.5M)

L = 14/3 M

14/3 M = M + 396

11/3 M = 396

M = 3/11 × 396

M = 108

L = M + 396

L = 108 + 396

L = 504

J = 3/4 L

J = 3/4 × 504

J = 378

M + L + J = 108 + 504 + 378 = 990

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3 years ago
Sarah and her friends laid down two beach blankets. The blankets are the same length but of different widths. The distributive p
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Answer:The width of the orange blanket is 23 inches.

Step-by-step explanation:

The total of both lengths is 75.We know  that the green blanket is 52 so 75-52 = 23 which is the width of the orange blanket

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In a gambling game a person draws a single card from an ordinary 52-card playing deck. A person is paid $17 for drawing a jack o
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Answer:

E.G=\$2

Step-by-step explanation:

Sample size 52 card

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Pay for others =-\$2

Therefore

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Probability or drawing King or Ace

P(K or A)=\frac{8}{52}

Probability or drawing Other cards

P(O)=\frac{36}{52}

Therefore

Expected Gain is mathematically given as

E.G=\sum_xP(x)

E.G=17*\frac{8}{52}+5*\frac{8}{52}+(-2)*\frac{36}{52}

E.G=\$2

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3 years ago
How can I rewrite this in exponential form and then evaluate it?
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QUESTION:- EVALUATE THE EXPRESSION

EXPRESSION:-

{( \sqrt[6]{27 {a}^{3}  {b}^{4} } )}^{2}

<h3>ANSWER-></h3>

{( \sqrt[6]{27 {a}^{3}  {b}^{4} } )}^{2}  \\ {( {27 {a}^{3}  {b}^{4} } )}^{ \frac{2}{6} }  \\ {({27 {a}^{3}  {b}^{4} } )}^{ \frac{ \cancel{2}}{ \cancel6 {}^{ \:  3} } } \\ {(27)}^{ \frac{1}{3} }  {a}^{ \frac{3}{3} }  {b}^{ \frac{4}{3} } \\{(3)}^{ \frac{ \cancel3}{ \cancel3} }  {a}^{ \frac{ \cancel3}{ \cancel3} }  {b}^{\frac{3 + 1}{3} } \\3a {b}^{ \frac{ \cancel3}{ \cancel3} }  {b}^{ \frac{1}{3} } \\ ANSWER->3ab \sqrt[3]{b}  \:  \:  \:  \:  \: or \: \: 3a {b}^{ \frac{4}{3} }

6 0
3 years ago
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