Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
(3x19.95+23.5+124.95)1.05=
59.85+23.5+124.95 =208.3
208.3×1.05=218.715
Answer:
When you move down you subtract and when you move to the right you subtract when your moving up or to the left you add. hope that helped :-)
Step-by-step explanation:
Hello there,
I hope you and your family are staying safe and healthy during this winter season.

We need to use the Quadratic Formula*
, 
Thus, given the problem:

So now we just need to plug them in the Quadratic Formula*
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As you can see, it is a mess right now. Therefore, we need to simplify it
, 
Now that's get us to the final solution:
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It is my pleasure to help students like you! If you have additional questions, please let me know.
Take care!
~Garebear
Answer:
116
Step-by-step explanation:
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