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3 years ago

What is a factor of 21 but not a multiple of 7 A.2 B.3 C.5 D.4

Mathematics

2 answers:

Nitella [24]3 years ago

6 0

It's 3.........................................

marissa [1.9K]3 years ago

6 0

It's b.3...........mssnsj

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(2a-16)+(3a+18)=17 what is a?

Volgvan

Hope this is the right answer .

3 0

2 years ago

What is 12 over three equals four over one

Phoenix [80]

<h2><em>It's exactly what it says. 12/3 = 4. 4/1 = 4. Thus, 4 = 4. It's already solved.</em></h2>

4 0

2 years ago

Read 2 more answers

A square piece of paper has an area of x2 square units. A

Dmitry_Shevchenko [17]

Answer:

Length of rectangular strip = 12

area of rectangular strip = 2*12 = 24

Area of square = x^2 = 12^2 = 144

Step-by-step explanation:

Area of square x^2

area of rectangle is given by length * width

Length of rectangular strip = x

width of rectangular strip = 2

area of rectangular strip = length * width = 2*x = 2x

Area of square piece of paper when rectangular strip is taken away from it

= Area of square - area of rectangular strip

= $x^2 -2x$

It is given that Area of square piece of paper when rectangular strip is taken away from it is 120 square units.

Thus,

$x^2 -2x = 120\\=> x^2 -2x -120 = 0\\=> x^2 -12x +10x-120\\=> x(x-12) +10(x-12)\\=> (x+10)(x-12) = 0\\\\$

Thus,

either x+10 = 0 or x -12= 0

x = -10 or x = 12

but length cannot be negative hence neglecting x = -10

hence value of x is 12.

Hence,

Length of rectangular strip = 12

area of rectangular strip = 2*12 = 24

Area of square = x^2 = 12^2 = 144

5 0

3 years ago

Pre-Calc: Find all the zeros of the function.

uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)