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3 years ago

Which statement is always true about a trapezoid?

Mathematics

2 answers:

Marysya12 [62]3 years ago

8 0

4. It has exactly 2 parallel sides.

defon3 years ago

5 0

4. It has exactly 2 parallel sides.

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Factor x^2 + 5x + 10 completley

k0ka [10]

This should be the answer.

5 0

4 years ago

50 POINTS!!!!!!!

stira [4]

Answer:

For this transition of equations, the graph of g(x) will be translated left 2 units with respect to the graph of f(x), so your answer choice will be A.

Step-by-step explanation:

In this equation, g(x) is changed by adding 2 and closing part of the equation in parenthases, this results in the translation 2 units left, which can be proven by a graph and my answer.

3 0

3 years ago

In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O

Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0

3 years ago

Divide. Write the quotient in lowest terms. 5 divide 3 1/3

Step2247 [10]

Answer:

3/2 or 1 1/2

Step-by-step explanation:

5÷3 1/3

5/1 ÷ 10/3 because you have to get it into an improper fraction form in order to divide

5/1 × 3/10 because you have to multiply the first number by the reciprocal

5 and 10 cancel out so you would have 2 at the bottom

3/2 or 1 1/2

3 0

3 years ago

Find the annual rate of interest. Principal = 4600 rupees Period = 5 years Total amount = 6440 rupees Annual rate of interest =

Semmy [17]

Answer:

The rate of interest for compounded annually is 6.96 % .

Step-by-step explanation:

Given as :

The principal amount = Rs 4600

The time period = 5 years

The amount after 5 years = Rs 6440

Let The rate of interest = R %

From compounded method

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm Time}$

or, Rs 6440 = Rs 4600 × $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $\frac{6440}{4600}$ = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

or, 1.4 = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $(1.4)^{\frac{1}{5}}$ = 1 + $\dfrac{R}{100}$

or, 1.0696 = 1 + $\dfrac{R}{100}$

or, $\dfrac{R}{100}$ = 1.0696 - 1

Or, $\dfrac{R}{100}$ = 0.0696

∴ R = 0.0696 × 100

I.e R = 6.96

Hence The rate of interest for compounded annually is 6.96 % . Answer

5 0

3 years ago