A = a^2.....where " a " is the length of one side
A = 79
79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a
so the length of one side is approximately 8.89 ft <==
79 ft/s = 0.0240792 km/s
0.0240792 x 60 = 1.444752 km/minute
<span>1.444752 x 60 = </span><span>86.68512 km/hour
</span>
Ans: 86.69 km/h
C
step by step explanation:
The measure of center and range to be used to compare the population is the median and the inter quartile range.
<u>Explanation:</u>
You utilize the median and the interquartile range (IQR) to portray skewed distributions of information. To look at two populaces, utilize the mean and the MAD when the two populations are symmetric. Utilize the middle and the IQR when possibly one or the two circulations are slanted.
In statistics and probability theory, the median is the worth isolating the higher half from the lower half of an information test, a populace or a likelihood circulation. For an informational collection, it might be thought of as the "center" esteem.
1,000,000
If the number is 5-9 (in this case, the one in the hundred-thousands place), you round up. If lower, then round down
