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Lera25 [3.4K]
3 years ago
15

(3x^2+11x+4)+(-5x+x^2-13) standard form

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
The answer is 4x^2+6x-9
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According to the distributive property, a(5 + b) =
WINSTONCH [101]
The answer would be B
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Can someone help me with my math homework?
zhenek [66]

See explanations

Step-by-step explanation:

6. The fraction can be written as;

\frac{x^2}{2y} /\frac{y^2}{4} \\\\\frac{x^2}{2y} *\frac{4}{y^2} \\\\

Divide 4 by 2

=\frac{2x^2}{y^3}

7.

The fraction can be written as;

\frac{b^2}{6} /\frac{b}{a}

introduce product sign as

\frac{b^2}{6} *\frac{a}{b} \\\\=b*a/6\\=\frac{ab}{6}

8.

The fraction can be written as;

\frac{x}{y} /\frac{yx}{2}

Introduce product sign

\frac{x}{y} *\frac{2}{yx} \\\\=\frac{2}{y^2}

9.

The fraction can be written as;

\frac{x}{y^2} /\frac{x}{y} \\\\\\=\frac{x}{y^2} *\frac{y}{x} \\\\\\=\frac{1}{y}

10.

The fraction is simplified to;

\frac{x}{3y} /\frac{9}{x} \\\\\\\frac{x}{3y} *\frac{x}{9} =\frac{x^2}{27y}

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Simplifying complex fractions:brainly.com/question/12214941

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6 0
3 years ago
1,508 rounded to the nearest hundred
DENIUS [597]

Answer:

1,500

Step-by-step explanation:

hope this helped!

6 0
2 years ago
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The box plots below show attendance at a local movie theater and high school basketball games:
Firdavs [7]

Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35

From the data, we can say the following:

Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43

Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37

Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.

Answer: D
7 0
2 years ago
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10 points plz answer thx
amid [387]

Answer:

(   \sqrt[4]{81} ) {}^{3}

81 {}^{ \frac{1}{4}  \times 3}

81 {}^{( \frac{3}{4}) }

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