4209Answer:
Step-by-step explanation:
Magic
Answer:

Step-by-step explanation:
This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

Where <em>a</em> and <em>b </em> are the legs of the triangle and <em>c</em> is the hypotenuse.
In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

Substitute these values into the formula.

Solve the exponents.


Add.

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

The third side length is <u>8.</u>
Answer:
x=1/3
Step-by-step explanation:
9x+5-3=5
9x=3
x=1/3
Answer:
a. has one solution
b. infinite solution
Step-by-step explanation:
a.
2(x - 1) + 6 = 4x - 22
2x - 2 + 6 = 4x - 22
2x - 4x = 2 - 6 - 22
-2x = -26
x = 26/2
x = 13
b.
6(2x + 1) – 2 = 12x + 4
12x + 6 - 2 = 12x + 4
12x - 12x = 4 + 2 - 6
0 = 0