A(1.3) (3,1) idk if it’s right but seems like the right answer
6/7 would be tan A
hope this helps
The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
The coefficients here are 4, 32, and -24. The GCF of these values is 4.
As for the variables, the values are x^7, x^5, and x^4. The GCF is x^4
To factor this expression take out 4x^4 from each of the terms.
Coefficients should be divided by four and exponents should be subtracted by 4 since they have the same base (x).
The answer here is A.
Answer:
67.97
Step-by-step explanation:
let AC be length of ladder and BC be distance between ladder and wall and angle be theta
Now,
costheta=BC/AC
THETA =COS^-1(3÷8)
THETA=COS^-1(0.375)
THETA=67.97 DEGREE
