If you need help for all 3 questions then ok.
Here’s what you need to do. If they give you a rectangular prism with a side length of #, that number is the length, width and height. I’ll help you for the first picture. They asked how many cubic blocks with a SIDE LENGTH of 1/7 in can fill in a cube with the SIDE LENGTH of 3/7 in. Here is your equation: (3/7 x 3/7 x 3/7) / (1/7 x 1/7 x 1/7). That’s how you solve it. (The slash stands for division.) Now do the same thing with the other pictures. They will ask you how many blocks with a side length of # can fill in a prism with the length, width, and height (or just a side length without saying the l, w and h.) Hopefully this helped! If I got it wrong or if you need help cause you didn’t get what I mean, let me know.
bYe
<em>Question:</em>
<em>Triangles PQR and RST are similar right triangles. Which proportion can be used to show that the slope of PR is equal to the slope of RT?</em>
Answer:

Step-by-step explanation:
See attachment for complete question
From the attachment, we have that:





First, we need to calculate the slope (m) of PQR
Here, we consider P and R

Where


becomes
--------- (1)
Next, we calculate the slope (m) of RST
Here, we consider R and T

Where


becomes
---------- (2)
Next, we equate (1) and (2)

<em>From the list of given options (see attachment), option A answers the question</em>
Answer: the answer is c
Step-by-step explanation:
your welcome
Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore

