Answer:

Step-by-step explanation:
Given


Required
Determine the image P'
P' is calculated by multiplying P and k.
i.e.

This gives:



<em>Hence, the image P' after dilating P is (-10,-8)</em>
Answer:
The rate at which Perimeter of the square is increasing is
.
Step-by-step explanation:
Given:
Circumference of the circle = 
Rate of change of in circumference = 6 in/secs
We need to find the rate at which the perimeter of the square is increasing
Solution:
Now we know that;

Now we know that;
side of the square= diameter of the circle
side of the square = 
Now Perimeter of the square is given by 4 times length of the side.

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

But 
So we get;

Hence The rate at which Perimeter of the square is increasing is
.
Answer:
1.02
Step-by-step explanation:
Answer:
100 in = 180 out
107 in = 187 out
117 in = 197 out
Step-by-step explanation:
we know that when there was 102 in, there was 185 out. we can also see that when there's 105 in, there was 185 out. the system outputs the input + 80
100 + 80 = 180
107 + 80 = 187
117 + 80 = 197
Answer:
See below ~
Step-by-step explanation:
<u>Given</u>
- Area = 490 units²
- Width = 5x
- Length = 8x
Now, we know that : length x width = area
<u>Using the given values</u>
- (8x)(5x) = 490
- 40x² = 490
- x² = 490/40
- x² = 49/4
- x = √49/4
- x = 7/2 = 3.5
<u>Length (l)</u> = 8x = 8(3.5) = <u>28 units</u>
<u>Width (w)</u> = 5x = 5(3.5) = <u>17.5 units</u>