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sattari [20]
3 years ago
11

A car enters an interstate highway 20 mi north of a city. The car travels north at an average speed of 58 mph. Which equation mo

dels the car’s distance d from the city after traveling for h hours?
Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0
The answer would be 20 d = h + 58
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What are the coordinates of P' if P (-5,-4) undergoes a dilation, centered at the origin, with a scale factor of K=2?
Margaret [11]

Answer:

P' = (-10,-8)

Step-by-step explanation:

Given

P = (-5,-4)

k =2

Required

Determine the image P'

P' is calculated by multiplying P and k.

i.e.

P' = P * k

This gives:

P' = (-5,-4) * 2

P' = (-5* 2,-4* 2)

P' = (-10,-8)

<em>Hence, the image P' after dilating P is (-10,-8)</em>

7 0
2 years ago
a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t
Burka [1]

Answer:

The rate at which Perimeter of the square is increasing is \frac{24}{\pi} \ in/secs.

Step-by-step explanation:

Given:

Circumference of the circle = 2\pi r

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}

Now we know that;

side of the square= diameter of the circle

side of the square = 2r

Now Perimeter of the square is given by 4 times length of the side.

P=4\times 2r =8r

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}

But \frac{dr}{dt} =\frac{3}{\pi}

So we get;

\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\  in/sec

Hence The rate at which Perimeter of the square is increasing is \frac{24}{\pi} \ in/secs.

5 0
3 years ago
How much is 5 divided by 4.9​
jok3333 [9.3K]

Answer:

1.02

Step-by-step explanation:

8 0
3 years ago
Please worth 20 points
lianna [129]

Answer:

100 in = 180 out

107 in = 187 out

117 in = 197 out

Step-by-step explanation:

we know that when there was 102 in, there was 185 out. we can also see that when there's 105 in, there was 185 out. the system outputs the input + 80

100 + 80 = 180

107 + 80 = 187

117 + 80 = 197

8 0
2 years ago
Read 2 more answers
GIVING BRAINLIST!!!!! Given that the area of rectangle IJKL is 490 units^2, what are its length and width?
seropon [69]

Answer:

See below ~

Step-by-step explanation:

<u>Given</u>

  1. Area = 490 units²
  2. Width = 5x
  3. Length = 8x

Now, we know that : length x width = area

<u>Using the given values</u>

  • (8x)(5x) = 490
  • 40x² = 490
  • x² = 490/40
  • x² = 49/4
  • x = √49/4
  • x = 7/2 = 3.5

<u>Length (l)</u> = 8x = 8(3.5) = <u>28 units</u>

<u>Width (w)</u> = 5x = 5(3.5) = <u>17.5 units</u>

4 0
2 years ago
Read 2 more answers
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