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fenix001 [56]
4 years ago
10

Help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
ElenaW [278]4 years ago
7 0
So 20% is 1/5 as a percent.

So 1/5 multiplied by 5 equals 5/5, or 1.

So if 1/5 = 6, then 6 multiplied by 5, or 30, must equal 5/5, or 1.

So the total number of dolls in Amyia's doll collection is 30.
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An hour is 60 minutes so 80-60 = 20 so 1 hour and 20 minutes.
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3a \times x - y - x - y \\ 3a \times x - x - y - y \\ 3a \times  - 2y - \\  - 6ay

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4 years ago
Need help ASAP!!!!!!!!
Zanzabum

Answer:

This organism has many bright orange spikes on it's back. It had two antennas on its head. And is a mix of blue and purple for its body. Its body is skinny and long.

Step-by-step explanation:

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The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

7 0
3 years ago
Jack usually mows his lawn in 6 hours. marilyn can mow the same yard in 4 hours. How much time would it take for them to mow the
Anuta_ua [19.1K]

Answer:

2.4 hours or 2 hours and 24 minutes

Step-by-step explanation:

Jack mows 1/6 of the lawn per hour while Marilyn mows 1/4 of the lawn together. Adding up those rates yields in their combined mowing rate:

R = \frac{1}{6}+ \frac{1}{4}\\R=\frac{10}{24}

The time required for them to mow the entire lawn is:

t = \frac{1}{R}\\t = \frac{1*24}{10}\\ t=2.4\ hours

It would take them both 2.4 hours to mow the lawn together.

5 0
3 years ago
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