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CaHeK987 [17]
3 years ago
7

5d-2g=9: g solve for g. the final answer has to start with g=

Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0
The answers is g=-9/2+5/2d

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The sample space listing the eight simple events that are possible when a couple has three children is​ {bbb, bbg,​ bgb, bgg,​ g
Maksim231197 [3]

Answer:

S= {bbbb, bbgb,​ bgbb, bggb,​ gbbb, gbgb,​ ggbb, gggb,bbbg, bbgg,​ bgbg, bggg,​ gbbg, gbgg,​ ggbg, gggg}

P( getting four girls and no boys)=0.0625

Step-by-step explanation:

The sample space for having four children can be written as

Sample space=S= {bbbb, bbgb,​ bgbb, bggb,​ gbbb, gbgb,​ ggbb, gggb,bbbg, bbgg,​ bgbg, bggg,​ gbbg, gbgg,​ ggbg, gggg}

where b stands for boy and g stands for girl.

number of elements in sample space=n(S)=16

P( getting four girls and no boys)=?

getting four girls and no boys= {gggg}

n( getting four girls and no boys)=1

P( getting four girls and no boys)=n( getting four girls and no boys)/n(S)

P( getting four girls and no boys)=1/16

P( getting four girls and no boys)=0.0625

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3 years ago
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