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2 years ago

HELP ITS DUE iN 3 MINUTES

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

5 0

Answer:

acute and isosceles

Step-by-step explanation:

acute because all angles less than 90

isosceles because 2 sides are equal length

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PLEASE HELP !! ILL GIVE BRAINLIEST !!

Zina [86]

I believe the answer is the last on KJM and KJH

5 0

3 years ago

Given a line segment with endpoints A(16, 8) and B(1, 3) what are the coordinates of the

blondinia [14]

Answer:

The line segment partitioned two-fifths from A to B is (10,6)

Step-by-step explanation:

First point from A to B is (16,8)

than find the difference between A to B i.e B - A

(1,3)-(16,8) = (-15,-5)

To measure the (2/5) difference we will multiply (-15,-5) with (2/5) which is equal to (-6,-2)

Now Add the difference to the first coordinate (point A) gives

Point of division = (16,8)+(-6,-2)

Point of division = (16-6, 8-2)

Point of division = (10,6)

4 0

3 years ago

I’m slow and lazy and yeah sorry just at least help

Anna007 [38]

Answer:

2) x = 6 y = 7 3) x = -5 y= 2

Step-by-step explanation:

2) 10x - 8y = 4

2(-5x + 3y = -9)

-10x + 6y = -18

10x - 8y = 4 Add both equations together

-2y = -14

y = 7 Divide both sides by -2

10(x) - 8(7) = 4 Plug in 7 for the y to solve for x

10x - 56 = 4

+ 56 + 56 Add 56 to both sides

10x = 60

x = 6 Divide both sides by 10

3) Where the two lines intersect, that is the solution to x and y.

The lines intersect at (-5,2). x = -5 y = 2

3 0

3 years ago

(5x+3y=-3 | 3x – 3y =-21

disa [49]

Answer:

8x = -24 => x = -3

y = 4

Step-by-step explanation:

7 0

3 years ago

Graphing in Point-Slope Form y−y1=m(x−x1) Graph the equation y+7=−45(x−4) ?

nevsk [136]

Answer:

<h2>The graph is in the attachment.</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - a point on a line

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

We have the equation in a point-slope form:

$y+7=-\dfrac{4}{5}(x-4)$

$y-(-7)=-\dfrac{4}{5}(x-4)$

Therefore we have one point: (4, -7).

Convert to the slope-intercept form:

$y+7=-\dfrac{4}{5}(x-4)$ use the distributive property

$y+7=-\dfrac{4}{5}x+\left(-\dfrac{4}{5}\right)(-4)$

$y+7=-\dfrac{4}{5}x+\dfrac{16}{5}$

$y+7=-\dfrac{4}{5}x+3\dfrac{1}{5}$ subtract 7 from both sides

$y=-\dfrac{4}{5}x-3\dfrac{4}{5}$

Put x = -1 to the equation:

$y=-\dfrac{4}{5}(-1)-3\dfrac{4}{5}=\dfrac{4}{5}-3\dfrac{4}{5}=-3$

Therefore we have the second point (-1, -3).

3 0

3 years ago