What is the area of the figure?

Mathematics

1 answer:

mash [69]2 years ago

8 0

Check the picture below.

$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh\qquad \qquad A=\cfrac{1}{2}(12\sqrt{2})(12\sqrt{2})\implies A=6\sqrt{2}\cdot 12\sqrt{2} \\\\\\ A=6\cdot 12\sqrt{2}\cdot \sqrt{2}\implies \implies A=72(\sqrt{2})^2\implies A=72\cdot 2\implies A=144$

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If the function f(x) = -1/2x - 7 were graphed, which of the following would be true?

Fittoniya [83]

ANSWER

D. As the x-values increase, the y-values would decrease

EXPLANATION

The given function is
$y = - \frac{1}{2} x - 7$

The slope of this function is
$m = - \frac{1}{2}$

Since the slope is negative, there is a negative or an inverse relationship between x and y.

As the values of x increases, the values of y decreases.

Also, as the values of x decreases, the values of y increases.

The first option is not true because as x is becoming bigger and bigger negatively, y will become positive.

For instance, when
$x = - 40$
$y = - \frac{1}{2} ( - 40) - 7$

This implies that,

$y = 20 - 7 = 13$

Options B is obviously not true because the function has a negative relationship between x and y.

Option C is also false because, x can be positive since it is the independent variable.

See graph

Therefore, the correct answer is option D.