Answer:
The number of tablets that can be prepared is 3076.
Step-by-step explanation:
The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

The percentages of each component in the formula are:
Acetaminophen:
%
Chlorpheniramine maleate:
%
Dextromethorphan hydrobromide:
%
If 1 Kg=
mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

Since each tablet weighs 342 mg, the number of tablets that can be prepared is:

Which means that 3076 tablets can be prepared and a there will be a remanent of 0.923*342 mg = 315.69 mg of active ingredients.
15:24 to the lowest term is 5:8. This is because you divide each number by the same number. You will divided 15 and 24 by 3 to get 5:8.
You will need three roots for this, so we have
Let x = -30, -10 and +20
So the factors will be (x+30)(x+10)(x-20)
The divide it to 100, this will help bring the peak up and down
So the polynomial function R(x) will become
1/100 * (x+30)(x+10)(x-20)
R(x) = 1/100 * (x+30)(x+10)(x-20)
Finding the X-intercept:
Let R(x) = 0 and solve for x.
1/100 * (x+30)(x+10)(x-20) = 0
x = -30, -10, 20 are the x-intercepts.
Answer:
6
Step-by-step explanation:
By inscribed angle theorem
![(15x-23)\degree = \frac{1}{2}[360\degree-(91+135)\degree]\\(15x-23)\degree = \frac{1}{2}[360\degree-226\degree]\\(15x-23)\degree = \frac{1}{2}[134\degree]\\(15x-23)\degree = 67\degree\\15x-23 = 67\\15x = 67+23\\15x = 90\\x= \frac{90}{15}\\x=6](https://tex.z-dn.net/?f=%2815x-23%29%5Cdegree%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B360%5Cdegree-%2891%2B135%29%5Cdegree%5D%5C%5C%2815x-23%29%5Cdegree%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B360%5Cdegree-226%5Cdegree%5D%5C%5C%2815x-23%29%5Cdegree%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B134%5Cdegree%5D%5C%5C%2815x-23%29%5Cdegree%20%3D%2067%5Cdegree%5C%5C15x-23%20%3D%2067%5C%5C15x%20%3D%2067%2B23%5C%5C15x%20%3D%2090%5C%5Cx%3D%20%5Cfrac%7B90%7D%7B15%7D%5C%5Cx%3D6)