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Verizon [17]
3 years ago
11

Plz do it for meee x

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer:

2,400cm²

Step-by-step explanation:

FORMULA FOR VOLUME OF A CUBOID = L×B× H

WHERE L is LENGTH =20cm

B=15cm

H= 8cm

:• VOLUME=20cm ×15cm ×8cm

=2,400cm²

djyliett [7]3 years ago
5 0

Answer:

Volume = 2400 cm³

Step-by-step explanation:

<em>Volume of Cuboid = </em>Length*Width*Height<em />

<u><em>Where L = 20 cm, W = 8 cm and H = 15 cm</em></u>

Volume = 20*8*15

Volume = 2400 cm³

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Hello : 
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3 years ago
Solve the equation 425x=850
mina [271]

Answer:

x=2

Step-by-step explanation:

To solve this, you must isolate x. To do this, divide both sides by 425 because that is what x is being multiplied by (and dividing is its opposite). Then, you get the answer, x=2.

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3 years ago
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In 2010, a city's population was 1,405,233 and it was decreasing at a rate of 1.1%. At this rate when will the city's population
frez [133]
The equation
                                            P(t) = 1405233 * (1 - 0.011)^(t)
models the population at t years after 2010. Then, when P(t) = 1,200,000, we have
                                 1200000 = 1405233 * (0.989)^t
                                  (0.989)^t = 1200000/1405233
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This means 14.27 years after 2010. Therefore, the answer to this question is 2024.
7 0
3 years ago
What is the volume of a rectangular prism with a length of 1.4 meters, a width of 0.5 meter and a height of 1.8 meters?
AfilCa [17]

Answer:

1.26 m cubed

Step-by-step explanation:

1.4*.5*1.8= 1.26

8 0
2 years ago
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A player tosses a die 6 times.If gets a number 6 Atleast two times he wins 2 dollars ,otherwise he looses 1 dollar.. Find the ex
swat32

Answer:

E(x)=-0.2101

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)

Where x_1 and x_2 are the values that the variable can take and p(x_1) and p(x_2) are their respective probabilities.

So, a player can win 2 dollars or looses 1 dollar, it means that x_1 is equal to 2 and x_2 is equal to -1.

Then, we need to calculated the probability that the player win 2 dollars and the probability that the player loses 1 dollar.

If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:

P(a)=nCa*p^a*(1-p)^{n-a}

Where nCa=\frac{n!}{a!(n-a)!}

So, in this case, n is number of times that the player tosses a die and p is the probability to get a 6. n is equal to 6 and p is equal to 1/6.

Therefore, the probability  p(x_1) that a player get at least two times number 6, is calculated as:

p(x_1)=P(x\geq2)=1-P(0)-P(1) \\\\P(0) =6C0*(1/6)^{0}*(5/6)^{6}=0.3349\\P(1)=6C1*(1/6)^{1}*(5/6)^{5}=0.4018\\\\p(x_1)=1-0.3349-0.4018\\p(x_1)=0.2633

On the other hand, the probability p(x_2) that a player don't get  at least two times number 6, is calculated as:

p(x_2)=1-p(x_1)=1-0.2633=0.7367

Finally, the expected value of the amount that the player wins is:

E(x)=x_1*p(x_1)+x_2*p(x_2)\\E(x)=2*(0.2633)+ (-1)*0.7367\\E(x)=-0.2101

It means that he can expect to loses 0.2101 dollars.

3 0
3 years ago
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