<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
N = number of compounding periods
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625)
</span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906
</span>
/
<span>
<span>
<span>
0.0108235735
</span>
</span>
</span>
Years =
<span>
<span>
<span>
16.2692348382
</span>
</span>
</span>
Source Calculator
http://www.1728.org/compint.htm
Answer
-2
Step-by-step explanation:
learn how to do your work f^gg0+
No, he is not right.
Integer is a number that can be written without a fractional component, and 1 3/4 doesn't.
Here's an image for you to better understand.
