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Verizon [17]
3 years ago
11

Plz do it for meee x

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer:

2,400cm²

Step-by-step explanation:

FORMULA FOR VOLUME OF A CUBOID = L×B× H

WHERE L is LENGTH =20cm

B=15cm

H= 8cm

:• VOLUME=20cm ×15cm ×8cm

=2,400cm²

djyliett [7]3 years ago
5 0

Answer:

Volume = 2400 cm³

Step-by-step explanation:

<em>Volume of Cuboid = </em>Length*Width*Height<em />

<u><em>Where L = 20 cm, W = 8 cm and H = 15 cm</em></u>

Volume = 20*8*15

Volume = 2400 cm³

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Someone please help me
Inessa05 [86]

9514 1404 393

Answer:

  A.  16°

Step-by-step explanation:

Angle E corresponds to angle N, the third angle in ∆MNO. Its measure is ...

  ∠N = 180° -∠M -∠O

  ∠N = 180° -99° -65°

  ∠N = ∠E = 16°

6 0
2 years ago
Renna pushed the button for the elevator to go up, but it would not move. The weight limit for the elevator is 450 kilograms, bu
Marina CMI [18]
First we should figure out how much over the weight limit the passengers are. We can find this by 750-450 which is 300. The amount of weight that needs to get off the elevator is 300 kilograms. Then, we know that each passenger weighs 70 kilograms. We can represent this as 70p.The inequality is 70p \geq 300. Then we can solve by dividing both sides of the inequality by 70. We get p \geq 4.28... Since people only come in whole numbers, and it has to be greater than 4.28, the number of excess passengers is 5.

Hope this helped!
8 0
3 years ago
Read 2 more answers
1/3 off the regular price of $51
jolli1 [7]

Answer:

34.00

Step-by-step explanation:

because get the discounted price, subtract the discount from the original price. To illustrate this principle, here is an example: to take 1/3 off $36.00, divide 36 by 3 and multiply by 1. This becomes 36/3 x 1 to equal 12, which represents a discount of $12.00

8 0
2 years ago
What is the theoretical probability of the spinner landing on a 5
Katarina [22]
The correct answer is 1/8.
6 0
2 years ago
Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)
Triss [41]

g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}

The surface element is

\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

and the integral is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)

###

To compute the last integral, you can integrate by parts:

u=r\implies\mathrm du=\mathrm dr

\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}

\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr

For this integral, consider a substitution of

r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds

\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds

\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds

=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds

and the result above follows.

4 0
3 years ago
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