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3 years ago

Need help Asap

1 answer:

7 0

X = 44/23 and y= -5/23.

We want the coefficient of one of the variables to be the same in both equations; we can multiply the top equation by 3 and the bottom equation by 2 to make the coefficients of y equal:
3(10x-4y=20) → 30x-12y=60
2(8x+6y=14) → 16x+12y=28

This is possible due to the multiplication property of equality.

Now that the coefficients of y are the same, we can add the equations together (using the addition property of equality):
30x+16x = 60+28
46x = 88 (addition of like terms)

Divide both sides by 46:
46x/46 = 88/46 (division property of equality)
x = 88/46 = 44/23

Now we substitute x into the first equation:
10(44/23) - 4y = 20
440/23 - 4y = 20

It will be easier to solve this if we have a common denominator; 20 wholes = (20*23)/23 = 460/23;

440/23 - 4y = 460/23

Subtract 440/23 from both sides (subtraction property of equality):
440/23 - 4y - 440/23 = 460/23 - 440/23
-4y = 20/23

Divide both sides by -4 (division property of equality):
-4y/-4 = 20/23 ÷ -4/1
y = 20/23 × -1/4 = -20/92 = -5/23

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HELLPP PLEASE OMGG I WILL GIVE YOU ALL MY POINTSS

weeeeeb [17]

Answer:

I believe it is $60

Step-by-step explanation:

She had $10. Her mom gave her $30 more. Her dad had given her $30.Her aunt and uncle gave her $100 more. She had another $20. It gives you the hints in the text.

Hope this helps!

6 0

3 years ago

Read 2 more answers

Find the volume of a pyramid with a square base, where the area of the base is

Firlakuza [10]

Answer:

Volume, $V= 75.35\ \text{feet}^3$

Step-by-step explanation:

We have,

Area of the base of of a pyramid with a square base is 12.7 ft

Height of the pyramid is 17.8 ft

It is required to find the volume of of a pyramid with a square base.

The formula used to find the volume of a pyramid with a square base is given by :

$V=\dfrac{1}{3}Ah$

Plugging all the values in above formula

$V=\dfrac{1}{3}\times 12.7\times 17.8\\\\V=75.35\ \text{feet}^3$

So, the volume of a pyramid is $75.35\ \text{feet}^3$ .

4 0

3 years ago

Help me please need help

Inga [223]

Answer:

Step-by-step explanation:

1. x -> opposite side of 48°

o → hypotenuse

b → adjacent side of 48°

$\sf Sin \ 48^\circ = \dfrac{opposite \ side }{hypotenuse}\\\\\\0.7431 = \dfrac{15}{o}\\\\\\0.74 * o = 15\\\\\\ o = \dfrac{15}{0.74}\\\\\\$

o = 20.27

$\sf cos \ 48^\circ = \dfrac{adjacent \ side }{hypotenuse}\\\\\\0.67 =\dfrac{b}{o}\\\\\\0.67=\dfrac{b}{20.27}$

b = 0.67*20.27

b = 13.58

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

2) i → opposite side of 25°

n → adjacent side of 25°

$\sf Sin \ 25 =\dfrac{i}{t}\\\\\\0.42=\dfrac{i}{30}\\\\\\0.42*30=i$

i = 12.6

$\sf Cos \ 30^\circ =\dfrac{n}{t}\\\\0.91=\dfrac{n}{30}\\\\\\0.91*30 = n$

n = 27.3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

3) a → opposite side of 70°

e → adjacent side of 70°

$Sin \ 70^\circ =\dfrac{a}{l}\\\\0.94 =\dfrac{a}{25}\\\\0.94*25=a$

a = 23.5

$\sf Cos \ 70^\circ =\dfrac{e}{l}\\\\0.34=\dfrac{e}{25}\\\\0.34*25=e$

e = 8.5

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$\sf Sin \ 52^\circ = \dfrac{x}{75}\\\\0.79*75=x\\$

x = 59.25

$\sf Cos \ 52^\circ = \dfrac{z}{75}\\\\0.62*75 =z$

z = 46.5

8 0

3 years ago

The Office of Student Services at UNC would like to estimate the proportion of UNC's 34,000 students who are foreign students. I

Pachacha [2.7K]

Answer:

Mean is 3.05

Standard deviation is 1.69.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are foreign, or they are not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The probability of x sucesses on n repeated trials, with p probability.

In this problem, we have a sample of 50 students, so $n = 50$ . The proportion of all UNC students that are foreign students is 0.061, so $p = 0.061$ .