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Nataliya [291]
3 years ago
6

One step equations explanation.

= - 91" alt=" - 7y = - 91" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
vagabundo [1.1K]3 years ago
6 0

divide by -91/7 answer is 13

melisa1 [442]3 years ago
5 0

Here we are given this linear equation with one variable y.

Now we have -7 in multiplication with y on the left side.

We perform opposite operation of multiplication to solve this equation.

so opposite operation of multiplication is division.

Dividing both sides by -7 we have

\frac{-7y}{-7} =\frac{-91}{-7}

so we have y=13


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Veronica tried to solve an equation step by step.
Svetach [21]
No steps are wrong. To solve this equation, you need to isolate the y. So, you would add 4.6 to both sides to cancel out the 4.6 on the right side and isolate the y.
3 0
2 years ago
What is the equation of the following line? Be sure to scroll down first to see
topjm [15]

Answer: (f)

Step-by-step explanation:

Given

Line that passes through (-\frac{1}{2},3) and (0,0)

Using two point form, equation of a line is given by

\Rightarrow \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}

Insert the values

\Rightarrow \dfrac{y-0}{x-0}=\dfrac{3-0}{-\frac{1}{2}-0}\\\\\Rightarrow \dfrac{y}{x}=-6\\\\\Rightarrow y=-6x

Thus, option (f) is correct

8 0
2 years ago
At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
MAXImum [283]

<u>Answer-</u>

At x= \frac{1}{2304e^4-16e^2} the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}

Here,

y=4e^{x}

Then,

{y}' = 4e^{x} \ and \ {y}''=4e^{x}

Putting the values,

K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

 {k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}

Now, equating this to 0

(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0

\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})

\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})

\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}

\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}

\Rightarrow 2304e^{2x}-16e^{2x}-1=0

Solving this eq,

we get x= \frac{1}{2304e^4-16e^2}

∴ At  x= \frac{1}{2304e^4-16e^2} the curvature is maximum.




6 0
2 years ago
WILL GIVE BRAINLIEST
erma4kov [3.2K]

Answer:

y = mx + b is the answer

Step-by-step explanation:

im a good teacher and i done this before

6 0
2 years ago
I know the answer but I don’t know how to set it up
vladimir2022 [97]

Answer: 4 x 16 = 64

16 + 44 = 60

I think..

Step-by-step explanation:

7 0
3 years ago
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