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Amiraneli [1.4K]
2 years ago
8

Write a function of the geometric sequence with a starting term of 8 and a common ratio of 2. Find the fourth term.

Mathematics
1 answer:
Andreas93 [3]2 years ago
7 0

The expression that represents well the <em>geometric</em> sequence is f(n) = 8 \cdot 2^{n-1} and the value of the <em>fourth</em> term is 64. (Correct choice: B)

<h3>How to analyze geometric sequences</h3>

<em>Geometric</em> sequences are <em>exponential</em> expressions with discrete domain, whose form is presented and explained below:

f(n) = a \cdot r^{n-1}, where a, r are <em>real</em> numbers and n is a <em>natural</em> number.     (1)

Where:

  • Value of the starting term.
  • Common ratio of the series.

According to the statement, we know that the first term of the <em>geometric</em> sequence is 8 and between any two <em>consecutive</em> terms there is a <em>common</em> ratio of 2. If we know that a = 8, r = 2 and n = 4, then the fourth term of the series by means of (1) is:

f(4) = 8 \cdot 2^{4-1}

f(4) = 8 · 8

f(4) = 64

The expression that represents the <em>geometric</em> sequence is f(n) = 8 \cdot 2^{n-1} and the value of the <em>fourth</em> term is 64.

To learn more on geometric sequences: brainly.com/question/11266123

#SPJ1

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