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3 years ago

How many metres in 4 and half kilometres

Mathematics

1 answer:

Delicious77 [7]3 years ago

8 0

There are 4500 meters because 1 kilometer is equal to 1000meters

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The preimage is reflected in line k, then in line m. Describe a single transformation that maps the blue figure to the green fig

inna [77]

I dont know but like mu comment i need ponits

7 0

3 years ago

Johnson Chemicals is considering two options for its supplier portfolio. Option 1 uses two local suppliers. Each has a "unique-e

sashaice [31]

Answer:

a) P=0.0175

b) P=0.0189

Step-by-step explanation:

For both options we have to take into account that not only the chance of a "superevent" will disable both suppliers.

The other situation that will disable both is that both suppliers have their "unique-event" at the same time.

As they are, by definition, two independent events, we can calculate the probability of having both events at the same time as the product of both individual probabilities.

a) Then, the probability that both suppliers will be disrupted using option 1 is

$P_1=P_{se}+P_{ue}^2=0.015+(0.05)^2=0.015+0.0025=0.0175$

b) The probability that both suppliers will be disrupted using option 2:

$P_2=P_{se}+P_{ue}^2=0.002+(0.13)^2=0.002+0.0169=0.0189$

Pue = probability of a unique event

Pse = probability of a superevent

3 0

3 years ago

What's 2 meters to 76 centimeters in simplest form

Komok [63]

Answer:

I am not really getting your question. Could you comment on this answer?

1 meter = 100 centimeters

Ratio:

2 m : 76 cm

200 cm : 76 cm

2 m : 0.76 m

6 0

3 years ago

Solve 3a+2+3a+7 using distributive property

marshall27 [118]

Answer:6a+9

Step-by-step explanation:

You cant combine a number with a variable that doesn’t have a variable

3 0

3 years ago

Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!

Nadya [2.5K]

QUESTION 1

If a function is continuous at $x=a$ , then $\lim_{x \to a}f(x)=f(a)$

Let us find the limit first,

$\lim_{x \to 4} \frac{x-4}{x+5}$

As $x \rightarrow 4$ , $x-4 \rightarrow 0$ , $x+5 \rightarrow 9$ and $f(x) \rightarrow \frac{0}{9}=0$

$\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0$

Let us now find the functional value at $x=4$

$f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0$

Since

$\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4)$ , the function is continuous at $a=4$ .

QUESTION 2

The correct answer is table 2. See attachment.

In this table the values of x approaches zero from both sides.

This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.

The values are also very close to zero unlike those in table 4.

The correct answer is B

QUESTION 3

We want to evaluate;

$\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}$

using the properties of limits.

A direct evaluation gives $\frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}$ .

This indeterminate form suggests that, we simplify the function first.

We factor to obtain,

$\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}$

We cancel common factors to get,

$\lim_{x \to 1} (x+3)^2$

$=(1+3)^2=16$

The correct answer is D

QUESTION 4

We can see from the table that as x approaches $-2$ from both sides, the function approaches $-4$

Hence the limit is $-4$ .

See attachment

The correct answer is option A

3 0

3 years ago