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Tpy6a [65]
3 years ago
7

If you subtract 13 from an even number, the answer will be odd. A. True B. False

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

A. True

Step-by-step explanation:

Even numbers are divisible by 2 with no remainder. 13/2 = 6.5 so yes.

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If it took 28 minutes to run 4 miles, then at that rate, how long would it take to run 20 miles?
SSSSS [86.1K]

Answer:

140 minutes

Step-by-step explanation:

After 28 mins you've gone 4 miles, assuming this rate is constant and you dont slow down or speed up, in order to get to 20 miles you will have run 5x as much (20/4 = 5), thus 5x the amount of time (28x5).

20/4 = 5

5x28 = 140

8 0
3 years ago
Read 2 more answers
Which is the solution to the inequality?
I am Lyosha [343]

Answer: A

Step-by-step explanation:

Subtract 12 from both sides:

y + 15 - 15 < 3 - 15

Simplify:

y < -12

8 0
2 years ago
Which number is not greater than 0.6
polet [3.4K]
0-0.59 because the number has to be less than 0.6 and all numbers up to 0.59 are not greater than 0.6
3 0
3 years ago
Points scored in a basketball game vary directly with shots taken. If a player scores 50 points and takes 40
KATRIN_1 [288]

Answer:

She would have scored 75 points.

Step-by-step explanation:

Points scored in a basketball game vary directly with shots taken.

This means that this question can be solved by proportions, using a rule of three.

How many would she have scored if she takes 60 shots?

Using a rule of three:

50 points - 40 shots

x points - 60 shots

Applying cross multiplication:

40x = 50*60

Dividing both sides by 40

x = 50*1.5 = 75

She would have scored 75 points.

6 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
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