Answer:
Option C 
Step-by-step explanation:
we have
The compound inequality can be divided into two inequality
-----> inequality A
----> inequality B
Solve inequality A
Divide by -3 both sides
when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol
Rewrite
The solution of the inequality A is the interval (-∞,-3]
Solve the inequality B
Divide by -3 both sides
when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol
The solution of the inequality B is the interval [-6,∞)
The solution of the compound inequality is
[-6,∞) ∩ (-∞,-3]=(-6,-3]
The triangle pairs that can be mapped to each other using a reflection and a translation is; Option B
<h3>How to Interpret Triangle Transformations?</h3>
Let us analyze each of the graphs;
Option A; This graph didn't use a reflection and a translation because we see that there was first a reflection across side QR and then another reflection across side AR.
Option B; This graph is correct as it made use of a reflection and a translation as seen in the attached graph.
Option C; This didn't use of a reflection and a translation because it instead carried out translation both in vertical and horizontal direction.
Option D; This carried out Translation and Rotation.
Read more about Triangle Transformations at; brainly.com/question/26261650
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Answer:
V(x,y,z) ≈ 61.2 in
Step-by-step explanation:
for the function f
f(X)=x³
then the volume will be
V(x,y,z)= f(X+h) - f(X) , where h= 0.2 (thickness)
doing a Taylor series approximation to f(x+h) from f(x)
f(X+h) - f(X) = ∑fⁿ(X)*(X-h)ⁿ/n!
that can be approximated through the first term and second
f(X+h) - f(X) ≈ f'(x)*(-h)+f''(x)*(-h)²/2 = 3*x²*(-h)+6*x*(-h)²/2
since x=L=10 in (cube)
f(X+h) - f(X) ≈ 3*x²*(-h)+6*x*(-h)²/2 = 3*L²*h+6*L*h²/2 = 3*L*h*(h+L)
then
f(X+h) - f(X) ≈ 3*L*h*(h+L) = 3* 10 in * 0.2 in * ( 0.2 in + 10 in ) = 61.2 in
then
V(x,y,z) ≈ 61.2 in
V real = (10.2 in)³-(10 in)³ = 61 in
There will be an 1/2 probability
what are the minimum, first quartile , median, third quartile , and maximum of the data set 20,70,13,15,23,17,40,51
Butoxors [25]
First put the data in order from least to greatest.
13, 15, 17,20] [23, 40, 51, 70
Min: 13
Q1: (middle of the lower half) (15 + 17)/2 = 16
Median: )middle of the data set) (20+23)/2=21.5
Q3:(middle of the upper half) (40+51)/2= 45.5
Max: 70
