The expression to find the value of the final angle of the triangle will be 180° - 40° - α.
<h3>How to solve the triangle?</h3>
Your information is incomplete as the triangle isn't attached. Therefore, an overview will be given.
Firstly, it's important to know that the total angle in a triangle is 180°. A triangle has three sides. In this case, angle B is given as α.
Let's assume that another angle is given as 40°. Therefore, the expression to find the value of the final angle will be 180° - 40° - α
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What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
I think the answer be C? Sorry if it's wrong