sen bu me bu set an sus ye babe smnsnssnnsnsnsnsnsnsnsns
 
        
             
        
        
        
Answer:
96 ways
Step-by-step explanation:
Given

Required
Ways to divide it into period of seconds
What this question implies is to determine the total number of factors of 86400
To start with, we determine the prime factorization of 86400
To do this, we continually divide 86400 by 2; when it can not be further divided, we divide by 3, then 7, then 11...












This implies that:

The number of factors d is the solved by:

Where

By comparison:



So:



<em>Hence, there are 96 total ways</em>
 
        
             
        
        
        
Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
![1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s](https://tex.z-dn.net/?f=1%20%3D%20500%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7B500%7D%20%3D%20%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%3D%20log%20%5B%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20log%280.5%29%5C%5C%5C%5C-2.699%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20%28-0.301%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.699%20%5Ctimes%2034%7D%7B0.301%7D%20%5C%5C%5C%5Ct%20%3D%20304.8%20%5C%20s)
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.
 
        
             
        
        
        
Answer: 
a) 48.21 %
b) 45.99 %
c) 20.88 %
d) 42.07 %
e) 50 %
Note: these values represent differences between z values and the mean
Step-by-step explanation:
The test to carry out is:
 Null hypothesis  H₀    is                           μ₀ = 30  
The alternative hypothesis                      m  ≠ 30
In which we already have the value of z for each case therefore we look  directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)
a)  z = 2.1   correspond to  0.9821  but mean value is ubicated at 0.5 then we subtract    0.9821 - 0.5  and get 0.4821   or 48.21 %
b)  z = -1.75   P(m) = 0.0401     That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %
c)  z = -.55    P(m) = 0.2912    and this value  for same reason as before is 0.5 - 0.2912 = 0.2088  or 20.88 %
d)  z = 1.41     P(m) = 0.9207    0.9207 -0.5     0.4207  or  42.07 %
e)  z = -5.3   P(m) = 0    meaning there is not such value in z table is too small to compute  and difference to mean value will be 0.5  
d)  z= 1.41      P(m) = 
 
        
             
        
        
        
Answer:
the first one should be -548
Step-by-step explanation:
plug in the values and you should get -30+7(-72-2).