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jok3333 [9.3K]
3 years ago
15

A. -5 B. 4 C. -4 D. 5

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0
The answer is D. In the function y=4/(x-5), A value of 5 would make the denominator 0. This is undefined, so 5 is excluded.
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Calcula la aceleración que debe tener un auto para alcanzar una velocidad de 108 km/h en 10 s si parte del reposo. ¿Qué distanci
sashaice [31]

sen bu me bu set an sus ye babe smnsnssnnsnsnsnsnsnsnsns

6 0
2 years ago
A day can be evenly divided into 86,400 periods of 1 second; 43,200 periods of each 2 seconds; or in many other ways. In total,
Leni [432]

Answer:

96 ways

Step-by-step explanation:

Given

Day = 86400\ seconds

Required

Ways to divide it into period of seconds

What this question implies is to determine the total number of factors of 86400

To start with, we determine the prime factorization of 86400

To do this, we continually divide 86400 by 2; when it can not be further divided, we divide by 3, then 7, then 11...

86400/2 = 43200

43200/2=21600

21600/2=10800

10800/2=5400

5400/2= 2700

2700/2 = 1350

1350/2=675

675/3=225

225/3=75

75/3=25

25/5=5

5/5 = 1

This implies that:

86400 = 2^7 * 3^3 * 5^2

The number of factors d is the solved by:

d = (a+1)*(b+1) *(c+1)

Where

n = 2^a * 3^b * 5^c

By comparison:

a = 7

b = 3

c=2

So:

d = (7+1)*(3+1) *(2+1)

d = 8*4 *3

d = 96

<em>Hence, there are 96 total ways</em>

7 0
3 years ago
Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
Newly purchased tires of a particular type are supposed to be filled to a pressure of 30 psi. Let m denote the true average pres
dimulka [17.4K]

Answer:

a) 48.21 %

b) 45.99 %

c) 20.88 %

d) 42.07 %

e) 50 %

Note: these values represent differences between z values and the mean

Step-by-step explanation:

The test to carry out is:

Null hypothesis  H₀    is                           μ₀ = 30  

The alternative hypothesis                      m  ≠ 30

In which we already have the value of z for each case therefore we look  directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)

a)  z = 2.1   correspond to  0.9821  but mean value is ubicated at 0.5 then we subtract    0.9821 - 0.5  and get 0.4821   or 48.21 %

b)  z = -1.75   P(m) = 0.0401     That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %

c)  z = -.55    P(m) = 0.2912    and this value  for same reason as before is 0.5 - 0.2912 = 0.2088  or 20.88 %

d)  z = 1.41     P(m) = 0.9207    0.9207 -0.5     0.4207  or  42.07 %

e)  z = -5.3   P(m) = 0    meaning there is not such value in z table is too small to compute  and difference to mean value will be 0.5  

d)  z= 1.41      P(m) =

4 0
3 years ago
Evaluate each using the values given please help me
yaroslaw [1]

Answer:

the first one should be -548

Step-by-step explanation:

plug in the values and you should get -30+7(-72-2).

4 0
3 years ago
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