<span>To solve this problem, we can use this formula d = rd (distance = rates x time)
She runs at a speed of 9 mph and walks at a speed of 3 mph.
Her distance running is
d = 9tr
where tr is the time she spends running
Her distance walking is
d = 3tw
where tw is the time she spends walking
The distances are the same so
9tr = 3tw
We also know that the total time is 5 hours
tr + tw = 5
tr = 5-tw
Substitute this value of tr in the first equation
9tr = 3tw
9(5-tw) = 3tw
45-9tw = 3tw
45 = 12tw
3.75= tw
Denise will spend 3.75 hours (3 hours, 45 minutes) walking back and 1.25 hours (1 hour, 15 minutes) running.</span>
consider X-axis along the east-west direction and north-south direction along Y-axis
A = magnitude of distance traveled by hiker in north-east direction = 30 kilometer
θ = angle of direction of displacement of the hiker relative to x-axis or east direction = 45 degree counterclockwise
A' = component of distance traveled by the hiker along the east direction.
Since the angle is given with the x-axis, the Sin provides the component in Y-direction. hence
Using the equation
A' = A Sinθ
Inserting the values
A' = (30) Sin45
A' = 21.2 km
The unknown side lengths are
Large triangle 10
Medium triangle 2
Small triangle 12/5 or 2.4
Step-by-step explanation:
EFD to ABC is 0.4 or 2/5
EFD to GHI is 0.24 or 6/25
ABC to GHI is 0.6 or 6/10
I think you can do this way:
Volume = B*h where B is the area of the base.
B= 4 * 10 = 40
V= 40 * 15
V= 600 cm^3
